fix(w05): S0d 拆成 P-08/P-10 两个计划项各自绑 view;补齐 fresh() 三面旗;候选全放弃防死锁

Task 4 审查发现 S0d_master_data 固定单一 view 导致 P-10 那份件在引擎里永不可达
(剧本声明的 view 恒压过模型的 say.view),按裁决拆成 S0d_p08_master / S0d_p10_document
两个计划项,各自绑 p08-master-create / p10-document-create;caseFileModel 补
parts_profile_rows、新增哨兵 s_p08_created 串起两步的入场前提;说明书三处 itemId、
S0_bind 的 disable 提示、ASSESSMENT_PHASES 第一段随之更新。steps.test.ts 的 fresh()
补齐 input_confirmed_total / review_approved_total / landing_prepared_total 三面旗
(此前因未绑定名比较求值为假才没暴露)。S0d_p08_master 剧本加「至少留一颗候选」规则,
防止候选全被放弃导致 s_pns_resolved 永远不成立的死锁。46/46 测试与 typecheck 全绿。

Co-Authored-By: Claude Fable 5 <noreply@anthropic.com>
Claude-Session: https://claude.ai/code/session_01FJcX8A6TWp4GRs41TYryEh

activities/part-substitution-assessment/__tests__/steps.test.ts

@@ -33,6 +33,9 @@ const fresh = (input: Record<string, unknown>): Record<string, unknown> => ({
   [`${D}_pn_check_exists_status_abandoned`]: 0,
   [`${D}_input_gap_rows`]: 0,
   [`${D}_input_gap_missing`]: 0,
+  input_confirmed_total: 0,
+  review_approved_total: 0,
+  landing_prepared_total: 0,
   substitution_relation_rows: 0,
   substitution_relation_missing: 0,
   substitution_relation_analysis_status_fae_confirmed: 0,
@@ -136,7 +139,7 @@ describe('doneWhen —— 开局不许真,干完必须真', () => {
 describe('说明书与剧本的骨架', () => {
   it('五张卡的骨架都住在说明书里(压拍之后只有说明书还在)', () => {
     expect(NARRATIVE).toContain('"kind":"entry","itemId":"S0_bind"');
-    expect(NARRATIVE).toContain('"kind":"decide","itemId":"S0d_master_data"');
+    expect(NARRATIVE).toContain('"kind":"decide","itemId":"S0d_p08_master"');
     expect(NARRATIVE).toContain('"title":"数据工单 · 芯片主数据创建(P-08)');
     expect(NARRATIVE).toContain('"title":"数据工单 · 原厂技术资料创建(P-10)');
     expect(NARRATIVE).toContain('"title":"评估输入与资料补齐确认');
@@ -151,14 +154,28 @@ describe('说明书与剧本的骨架', () => {
     expect(s3).toContain('工具调用后同拍其余动作作废');
   });
 
-  it('S0 剧本写明库里都有就 disable S0d;S0d 剧本写明候选 ≥2 才问、=1 必建、原 PN 硬阻塞', () => {
+  it('S0 剧本写明库里都有就 disable S0d 两项;S0d_p08_master 剧本写明候选 ≥2 才问、=1 必建、原 PN 硬阻塞', () => {
     const s0 = ASSESSMENT_STEPS.find((s) => s.item === 'S0_bind')?.guide ?? '';
-    expect(s0).toContain('disable S0d_master_data');
-    const s0d = ASSESSMENT_STEPS.find((s) => s.item === 'S0d_master_data')?.guide ?? '';
+    expect(s0).toContain('disable S0d_p08_master');
+    const s0d = ASSESSMENT_STEPS.find((s) => s.item === 'S0d_p08_master')?.guide ?? '';
     expect(s0d).toContain('硬阻塞');
     expect(s0d).toContain('候选只有 1 颗');
   });
 
+  it('S0d 拆成两项各自绑自己的 view(P-10 那份件不会永远推不出来),两项都没有 doneWhen', () => {
+    const p08 = ASSESSMENT_STEPS.find((s) => s.item === 'S0d_p08_master');
+    const p10 = ASSESSMENT_STEPS.find((s) => s.item === 'S0d_p10_document');
+    expect(p08?.view).toBe('p08-master-create');
+    expect(p10?.view).toBe('p10-document-create');
+    expect(p08?.doneWhen).toBeUndefined();
+    expect(p10?.doneWhen).toBeUndefined();
+  });
+
+  it('候选放弃到只剩最后一颗时不许再放弃(至少留一颗,防止全放弃死锁)', () => {
+    const s0d = ASSESSMENT_STEPS.find((s) => s.item === 'S0d_p08_master')?.guide ?? '';
+    expect(s0d).toContain('至少留一颗候选');
+  });
+
   it('五段进度,每段名 ≤10 字;除放行外每项恰属一段', () => {
     expect(ASSESSMENT_PHASES).toHaveLength(5);
     for (const p of ASSESSMENT_PHASES) expect(p.name.length, p.name).toBeLessThanOrEqual(10);